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Mr. A forgot to write down a very important phone number. All he remembers is that it started with 713 and that the next set of 4 digits involved are 1, 7 and 9 with one of these number and appering twice. He guesses a phone number and dials randomly. The odds against of dialing the correct number is $\frac{m}{n}$ . Then least value of m+n is _____

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answer is 36.

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Detailed Solution

Total number of possible ways= $n (S) =^{4} P_{2} \times^{3} C_{1}$

Number of ways of dialing correct number =1

The odds against of dialing the correct number= $P (E) : P (E) = \frac{35}{36} : \frac{1}{36}$

$m / n = \frac{35}{1}$

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