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Multiply the binomials: (y − 8) and (3y − 4)

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3y² − 28y − 32

3y² + 28y + 32

3y² − 28y − 24

3y² − 28y + 32

answer is A.

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Detailed Solution

(y − 8)(3y − 4)

= y(3y − 4) − 8(3y − 4)

= y(3y) − y(4) − 8(3y) − 8(−4)

= 3y² − 4y − 24y + 32

= 3y² − 28y + 32

Hence, the product of (y − 8) and (3y − 4) is 3y² − 28y + 32.

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