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$^{(n + 1)} C_{1} +^{(n + 1)} C_{2} +^{(n + 1)} C_{3} + . .... +^{(n + 1)} C_{0} =$

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$2^{n + 1}$

$2 (2^{n} + 1)$

$2 (2^{n} - 1)$

$(2^{n + 1} - 1)$

answer is C.

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Detailed Solution

$^{(n + 1)} C_{0} +^{(n + 1)} C_{1} + ....... +^{(n + 1)} C_{n} +$
$...... +^{(n + 1)} C_{n + 1} {= 2}^{n + 1}$

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