n-butane is produced by monobromination of ethane followed by Wurtz reaction. Calculate volume of ethane in litres at 1 atm and 273K to produce 29 g of n-butane if bromination takes place with 80% yield and the Wurtz reaction with 56% yield. 
(C=12u, H=1u, Br=80). Adjust the value to nearest integer.

Calculation of Ethane Volume to Produce n-Butane

Given:

• Mass of n-butane = 29 g
• Bromination yield = 80%
• Wurtz reaction yield = 56%
• Molecular weights: n-butane (C₄H₁₀) = 58 g/mol, bromoethane (C₂H₅Br) = 109 g/mol, ethane (C₂H₆) = 30 g/mol

Steps:

1. Calculate moles of n-butane produced: 29 / 58 = 0.5 mol
2. Wurtz reaction requires 2 moles of bromoethane to produce 1 mole n-butane, adjusted for 56% yield: moles bromoethane needed = (2 × 0.5) / 0.56 ≈ 1.79 mol
3. Adjust for bromination yield (80%) to get moles of ethane: moles ethane needed = 1.79 / 0.8 ≈ 2.24 mol
4. Calculate volume of ethane at 1 atm and 273 K (1 mole = 22.4 L): Volume = 2.24 × 22.4 ≈ 50 L

Final Answer: The volume of ethane required is approximately 50 liters.