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Q.

n-factor of Potassium permanganate in strong alkaline medium is

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a

1

b

6

c

3

d

5

answer is A.

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Detailed Solution

n-factor of Potassium Permanganate (KMnO4) in Strong Alkaline Medium

In a strongly alkaline medium, potassium permanganate (KMnO4) is reduced from an oxidation state of +7 (as MnO4-) to +6 (as manganate ion, MnO42-).

Electron Change and n-factor

  • The change in oxidation state is from +7 to +6.
  • This involves a change of 1 electron per Mn atom.

Therefore, the n-factor of KMnO4 in strong alkaline medium is 1.

Comparison with Other Media

  • In acidic medium: n-factor = 5 (Mn7+ to Mn2+)
  • In neutral/weakly basic medium: n-factor = 3 (Mn7+ to Mn4+)
  • In strong alkaline medium: n-factor = 1 (Mn7+ to Mn6+)
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