Q.

n-factor of H3PO2 during its diproportionation is 3H3PO2PH3+2H3PO3
 

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answer is 1.33.

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Detailed Solution

nfactor measures the change in electrons taking place per molecule. In the given reaction, oxidation state of P in each compound is:

3H3P+1O2P-3H3+2H3P+3O3

Half cell reaction:

H3PO2H3PO3+2e oxidation 2H3PO22H3PO3+4e- reduction 3H3PO2+4ePH3+2H3PO3+4e (overall reaction)

nfactor is calculated as:

n-factor=number of electrons involvednumber of molecules involved=43=1.33

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