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Q.

N fundamental charges each of charge ‘q’ are to be distributed as two point charges separated by a fixed distance, then the maximum to minimum force bears a ratio (N is even and greater than 2 )

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a

(N-1)24N2

b

4 N2(N-1)

c

N24( N-1)

d

2N2(N-1)

answer is C.

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Detailed Solution

Given data: two-point charges separated by a set distance are to be dispersed among N basic charges, each of charge “q”.  

Concept used: coulomb’s law

Detailed solution:

We have N fundamental charges. Let nq be placed at one point 

So, (N-n) q planced at point

let fixed distance between both set of charges r

F=kq1q2r2=kq2r2n(N-n) 

[n(N-n)]max=N22 

[n(N-n)]min=N-1.1=N-1

 FmaxFmin=N24(N-1)

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N fundamental charges each of charge ‘q’ are to be distributed as two point charges separated by a fixed distance, then the maximum to minimum force bears a ratio (N is even and greater than 2 )