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Q.

N-H bond length(in pm) in ammonia is,

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answer is 101.7.

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Detailed Solution

Ammonia Molecule (NH₃) - Bond Angles

N H H H 101.7 pm 107.8°

Molecular Structure Details

Molecule: Ammonia (NH₃)

Central Atom: Nitrogen (N)

Bonded Atoms: Three Hydrogen (H) atoms

Lone Pairs: One lone pair of electrons on nitrogen

 

Bond Angles

Angle 1: 101.7 pm

This represents the bond angle between two N-H bonds (likely H-N-H angle)

Note: "pm" typically stands for picometers, but in this context, it appears to indicate an angular measurement. The standard H-N-H bond angle in ammonia is approximately 107°.

 

Angle 2: 107.8°

This represents another H-N-H bond angle in the ammonia molecule

Molecular Geometry

 

Electron Geometry: Tetrahedral

Molecular Geometry: Trigonal Pyramidal

Reason: The presence of one lone pair on the nitrogen atom pushes the three N-H bonds closer together, resulting in bond angles slightly less than the ideal tetrahedral angle of 109.5°.

The actual H-N-H bond angles in ammonia are approximately 107.8°, which is consistent with the VSEPR (Valence Shell Electron Pair Repulsion) theory.

 

Key Features

  • The nitrogen atom is at the center of the molecule
  • Three hydrogen atoms are bonded to nitrogen
  • One lone pair of electrons (shown as dots above N)
  • The dashed line to the bottom H indicates it's pointing away (into the page)
  • Green arrows indicate the bond angles being measured
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