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Q.

n identical cells are joined in series with its two cells A and B in the loop with reversed polarities. EMF of each cell is E and internal resistance r . Potential difference across cell A or B is (here n > 4)

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a

$\frac{2 E}{n}$

b

$2 E (1 - \frac{1}{n})$

c

$\frac{4 E}{n}$

d

$2 E (1 - \frac{2}{n})$

answer is D.

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Detailed Solution

$i = (\frac{n - 4}{nr}) E$
$& V_{A} = E + ir = E + (\frac{n - 4}{n}) E = 2 E (1 - \frac{2}{n})$

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n identical cells are joined in series with its two cells A and B in the loop with reversed polarities. EMF of each cell is E and internal resistance r . Potential difference across cell A or B is (here n > 4)