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Q.

‘n’ identical cells, each of e.m.f ‘E’ and internal resistance ‘ $r$ ’, are formed in series to form a closed circuit. One cell ‘A’ is joined with reversed polarity. The potential difference across each cell, except A, is

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a

$\frac{2 E}{n}$

b

$\frac{n - 1}{n} E$

c

$\frac{2 n}{n - 2} E$

d

$\frac{n - 2}{n} E$

answer is A.

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Detailed Solution

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$i = \frac{(n - 2) E}{n r}$

$V_{B} - V_{A} = - i r + E$

$= E - \frac{(n - 2) E}{n r} r$

$= \frac{2 E}{n}$

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