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n identical cells, each of emf and internal resistance r, are joined in series to form a closed circuit. One cell (A) is joined with reversed polarity. The potential difference across each cell, except A, is

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$\frac{2 ε}{n}$

$\frac{n - 1}{n} ε$

$\frac{n - 2}{n} ε$

$\frac{2 n}{n - 2} ε$

answer is A.

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Detailed Solution

$I = \frac{(n - 2) E}{n r}$ and $V = E - I r$

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