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$n$ identical cells, each of emf $E$ and internal resistance $r$ ,are joined in series to from a closed circuit. One cell $(A)$ is joined with reversed polarity. The potential difference across each cell, except $A,$ is

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$\frac{2 E}{n}$

$(\frac{n - 1}{n}) E$

$(\frac{n - 2}{n}) E$

$(\frac{2 n}{n - 2}) E$

answer is A.

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Detailed Solution

$I = \frac{(n - 2) E}{n r}$

voltage across one of the cells except A is

$V = E - I r$

$= E - \frac{(n - 2) E}{n r} = \frac{2 E}{n}$

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