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Q.

n identical light bulbs, each designed to draw P power from a certain supply, are joined in series across that supply. The total power which they will draw is

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a

Pn

b

np

c

Pn2

d

P

answer is A.

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Detailed Solution

Let R be the resistance of each bulb. Resistance of n bulbs = n R
Current in each bulb =i=VnR
Power drawn by each bulb
P2=i2R=V2n2R2×R=V2n2R=Pn2 R=V2P
Total power drawn =n×Pn2=Pn

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