Q.

N molecules each of mass m of a gas A and 2N molecules each of mass 2m of gas B are contained in the same vessel which is maintained at temperature T. The mean square velocity of molecules of B type is v2 and the mean square rectangular component of the velocity of A type is denoted by ω2. Then ω2v2:

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a

1

b

23

c

d

13

answer is D.

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Detailed Solution

Mean kinetic energy of the two types of molecules should be equal. 

The mean square velocity of A type molecules =ω2+ω2+ω2=3ω2

Therefore, 12m3ω2=12(2m)v2

This gives ω2v2=23

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N molecules each of mass m of a gas A and 2N molecules each of mass 2m of gas B are contained in the same vessel which is maintained at temperature T. The mean square velocity of molecules of B type is v2 and the mean square rectangular component of the velocity of A type is denoted by ω2. Then ω2v2: