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$n \in N,$ then the statement $8 n + 16 \leq 2^{n}$ is true for

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a

$n = 5$

b

$n = 2$

c

$n = 6$

d

$n = 3$

answer is C.

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Detailed Solution

Given statement $8 n + 16 \leq 2^{n}, n \in N$
$\Rightarrow 8 (n + 2) \leq 2^{n} (n + 2) \leq 2^{n - 3}$
Clearly, for $n = 6$
$(∵ 8 \leq 8)$

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n∈N, then the statement 8n+16≤2n is true for