N2(g)+3H2(g)⇌2NH3(g) at 300 KGiven Gas NH3 N2 H2 ΔfH0(J) −45×103 0 0 ΔS0(Jk−1) +200 +190 +130Calculate the value of Z.Where z=|(ΔrG0 in kJ)4|

N2+3H2⇌2NH3 ΔHf0=2ΔHf(NH3)0−ΔHf(N2)0−3ΔHf(H2)0 =−90×103−0−0=−90×103 ΔSr0=2SNH3−SN2−3SH2 =2×200−190−3×130 =−180 ΔGr0=ΔH0−TΔS0=−90×103−300×(−180)1000kJ =−36 kJ =|ΔG04|=364=9

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$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$ at 300 K
$\begin{array}{l} G i v e n G a s N H_{3} N_{2} H_{2} \\ Δ_{f} H^{0} (J) - 45 \times 10^{3} 0 0 \\ Δ S^{0} (J k^{- 1}) + 200 + 190 + 130 \end{array}$
Calculate the value of $Z .$
Where $z = | \frac{(Δ_{r} G^{0} i n k J)}{4} |$

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answer is 9.

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Detailed Solution

$N_{2} + 3 H_{2} ⇌ 2 N H_{3} Δ H_{f}^{0} = 2 Δ H_{f (N H_{3})}^{0} - Δ H_{f (N_{2})}^{0} - 3 Δ H_{f (H_{2})}^{0} = - 90 \times 10^{3} - 0 - 0 = - 90 \times 10^{3} Δ S_{r}^{0} = 2 S_{N H_{3}} - S_{N_{2}} - 3 S_{H_{2}} = 2 \times 200 - 190 - 3 \times 130 = - 180 Δ G_{r}^{0} = Δ H^{0} - T Δ S^{0} = \frac{- 90 \times 10^{3} - 300 \times (- 180)}{1000} k J = - 36 k J = | \frac{Δ G^{0}}{4} | = \frac{36}{4} = 9$