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Q.

 N2 + O2 → 2NO, ΔH = + Q1
N2 + 2O2 → N2O4, ΔH = – Q2
NO + 1/2O2 → NO2, ΔH = – Q3
2NO2 → N2O4, ΔH = – Q4, then

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a

Q2 = Q1(– Q3) + (– Q4)

b

– Q2 = Q1 – 2Q3 – Q4

c

Q1 + Q2= – (Q3 + Q4)

d

Q1 – Q4 = Q2 – Q3

answer is B.

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Detailed Solution

begin{array}{l} ,,,,,frac{1}{{eq.(1)}} Rightarrow 2NO to {N_2} + {O_2},Delta {H_1} = - {Q_1}\ ,,,,,,eq.(2) Rightarrow {N_2} + 2{O_2} to {N_2}{O_4},Delta {H_2} = - {Q_2}\ underline {2 times frac{1}{{eq.(3)}} Rightarrow 2N{O_2} to 2NO + {O_2},Delta {H_3} = + 2{Q_3}} \ ,,,,,,,,,,,,,,,,,,,,,,,,,,,,2N{O_2} to {N_2}{O_4},,,,,Delta {H_4} = - {Q_4} = 2{Q_3} - {Q_1} - {Q_2} end{array}

   

-Q_2=Q_1-2Q_3-Q_4
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