N2(g) + 2O2(g) →2NO2(g) + X kJ ; 2NO(g) + O2(g) →2NO2(g) + Y kJ ;then heat of formation of NO(g) is

N2g+2O2g→2NO2g:ΔH=−X kJ...1 ; 2NO2→2NO+O2..∆H=+YKJ....(2) ; 12N2+12O2→NO,∆H=? ; 12Eq1+12Eq2 ∆H = 12(Y-X)

N2(g) + 2O2(g) →2NO2(g) + X kJ ; 2NO(g) + O2(g) →2NO2(g) + Y kJ ;then heat of formation of NO(g) is

N2g+2O2g→2NO2g:ΔH=−X kJ...1 ; 2NO2→2NO+O2..∆H=+YKJ....(2) ; 12N2+12O2→NO,∆H=? ; 12Eq1+12Eq2 ∆H = 12(Y-X)

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N_2(g) + 2O_2(g) $\to$ 2NO_2(g) + X kJ ; 2NO_(g) + O_2(g) $\to$ 2NO_2(g) + Y kJ ;then heat of formation of NO_(g) is

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$2 X - 2 Y$

$X - Y$

$\frac{Y - X}{2}$

$\frac{X - Y}{2}$

answer is C.

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Detailed Solution

$N_{2} (g) + 2 O_{2} (g) \to 2 {NO}_{2} (g) : Δ H = - X kJ . . . (1); 2 {NO}_{2} \to 2 NO + O_{2} . . ∆ H = + YKJ . . . . (2); \frac{1}{2} N_{2} + \frac{1}{2} O_{2} \to NO, ∆ H = ?; \frac{1}{2} Eq (1) + \frac{1}{2} Eq (2) ∆ H = \frac{1}{2} (Y - X)$