${Na}_{2} {SO}_{4}$ is soluble in water white ${BaSO}_{4}$ is insoluble. Which of the reason is correct about the above statement.

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Hydration energy of BaSO₄ exceeds its lattice energy.

The solubility in H₂O of a compound depends only on its hydration energy.

The solubility in H₂O of a compound depends only on its lattice energy.

Lattice energy of BaSO₄ exceeds its hydration energy

answer is A.

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Detailed Solution

$For ionic compound if lattice energy (Δ_{u} H^{⊙}) > hydration$ $energy (Δ_{hyd} H^{⊖}) the compound is insoluble and vice versa.$

${Na}_{2} {SO}_{4}, Δ_{u} H^{⊖} < Δ_{hyd} H^{⊖}$ , thus it is soluble in H₂O.

$For {BaSO}_{4}, Δ_{u} H^{⊖} > Δ_{hyd} H^{⊖}, thus it is insoluble in H_{2} O .$

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