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Q.

Nearly how many grams of sucrose should be dissolved in 100g of water in order to produce a solution having a difference between the freezing point and the boiling point temperatures at 105.0 $°$ C?

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a

72

b

34.2

c

342

d

460

answer is B.

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Detailed Solution

Let the molality of the solution is m.

$∆ T_{f} = K_{f} \times m$ and $∆ T_{b} = K_{b} \times m$

$∆ T_{f} + ∆ T_{b} = (K_{f} + K_{b}) \times m \Rightarrow ∆ T_{f} + ∆ T_{b} = (1.86 + 0.51) \times m = 2.37 m$

So, $m = \frac{5}{2.37} = 2.1$

m = $\frac{x}{342} X \frac{1000}{100}$

x = 2.109 x 34.2 = 72.12

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Nearly how many grams of sucrose should be dissolved in 100g of water in order to produce a solution having a difference between the freezing point and the boiling point temperatures at 105.0°C?