Negation of the statement $:\sqrt{5}$ is an integer (or) 5 is irrational is

p$:\sqrt{5}$is an integer,

 q:5 is irrational

$\boxed{~(\mathrm{p}\vee \mathrm{q})\equiv \sim \mathrm{p}\wedge ~\mathrm{q}}$

Negation of the statement is

$\sqrt{5}$is not an integer and 5 is not irrational