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Q.

NH3 can be liberated when NH4+ salts react with

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a

NaOH

b

All

c

KOH

d

Ca(OH)2

answer is D.

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Detailed Solution

Ammoniumsalt + alkali\mathop \to \limits^\Delta N{H_3} \uparrow

\begin{gathered} NH_4^ + + O{H^ - } \to N{H_4}OH \to N{H_3} \uparrow + {H_2}O \\ N{H_4}Cl + NaOH\xrightarrow{\Delta }NaCl + N{H_3} \uparrow + {H_2}O \\ N{H_4}N{O_3} + NaOH\xrightarrow{\Delta }NaN{O_3} + N{H_3} \uparrow + {H_2}O \\ N{H_4}Cl + Ca{(OH)_2}\xrightarrow{\Delta }CaC{l_2} + N{H_3} \uparrow + {H_2}O \\ {(N{H_4})_2}S{O_4} + KOH \to {K_2}S{O_4} + N{H_3} \uparrow + {H_2}O \\ \end{gathered}

This is a prelimenary test to identify NH4+ salt and NH3 gas in the laboratory

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NH3 can be liberated when NH4+ salts react with