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${NH}_{3}$ is liquefied more easily than $N_{2} .$ Hence

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$a (N H_{3}) > a (N_{2}) b u t b (N H_{3}) < b (N_{2})$

a and b of $N H_{3}$ > that of $N_{2} .$

$a (N H_{3}) > a (N_{2}) b u t b (N H_{3}) > b (N_{2})$

None

answer is B.

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Detailed Solution

More is the value of a mass greater is the liquefaction and bigger is the size of molecule bigger is the ‘b’ value.

A gas can be liquified, when the value of ‘a’ dominates. ('a' describes the attractive interactions)

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