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${({NH}_{4})}_{2} {Cr}_{2} O_{7}$ on heating liberates gas. The same gas will be obtained by :

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Heating of ${NH}_{4} {NO}_{3}$

Heating of $H_{2} O_{2}$ with ${NaNO}_{2}$

Heating of ${NH}_{4} {NO}_{2}$

treating of ${Mg}_{3} N_{2}$ with water

answer is C.

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Detailed Solution

Heating of ${({NH}_{4})}_{2} {Cr}_{2} O_{7}$ liberates nitrogen gas.

${({NH}_{4})}_{2} {Cr}_{2} O_{7} \to N_{2} + {Cr}_{2} O_{3} + 4 H_{2} O$

Nitrogen gas also liberated when ${NH}_{4} {NO}_{2}$ heated.

${NH}_{4} {NO}_{2} \to N_{2} + 2 H_{2} O$

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