Nichrome and copper wires of same length and same radius are connected in series. Current I is passed through them. Which wire gets heated up more? Justify your answer.

Heat dissipate in a wire is given by the formula
$\begin{array}{l}\mathrm{H}={\mathrm{I}}^2\mathrm{Rt}\\ \mathrm{H}=\frac{{\mathrm{I}}^2\mathrm{\rho l}}{\mathrm{A}}\times \mathrm{t}\left(\therefore \mathrm{R}=\frac{\mathrm{pl}}{\mathrm{A}}\right)\end{array}$
When the same current flows in a circuit ‘i’, length (l) and area (A), H depends on
$\mathrm{H}\propto \rho$
${\mathrm{\rho }}_{\text{nichrome }}>{\mathrm{\rho }}_{\text{copper }}$
(Sinc, H is proportional to 𝜌) So,
${\mathrm{H}}_{\text{nichrome }}>{\mathrm{H}}_{\text{copper }}$