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Q.

Nitrous acid was disproportionated to form water. ${HNO}_{3}$ and X. In another reaction, sodium nitrite was reacted with $H_{2} {SO}_{4}$ to form ${NaHSO}_{4} . {HNO}_{3}$ . water and Y. That are X and Y respectively ?

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a

$NO . N_{2} O_{3}$

b

$N_{2} O . {NO}_{2}$

c

${NO}_{2} . N 2 O_{5}$

d

NO.NO

answer is B.

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Detailed Solution

Sodium nitrite is reacted with H₂SO₄to form NaHSO₄,HNO₃, water and NO gas (X). Gold is dissolved in aqua-regia to form water, AuCl₄− and
NO gas. Thus, here X is NO and Y is NO. Reactions involved are as follows : Sodium nitriteNaNO₂+H₂SO₄⟶NaHSO₄+HNO₃+H₂O+(X)NO
Au(s)+Aqua-regia HNO₃+4HCl⇌AuCl₄⁻+(Y)NO+H2O

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