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n+l value of an orbital is equal to 5. Total number of nodes the orbital must not posses is

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answer is D.

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Detailed Solution

n+l = 5 is possible for

5s orbital ,4p orbital and 3d orbital

total number of nodes = n -1

total number of nodes for 3d orbital = 3 - 1 = 2

total number of nodes for 4p orbital = 4 - 1 = 3

total number of nodes for 5s orbital = 5 - 1 = 4

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