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Q.

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A Copper plate is soldered between two steel plates. All the plates have the same cross- section (A ) and length l. The coefficient of thermal expansions are   {\alpha _c}and\,{\alpha _s}\ and their young’s moduli are {y_c}\,and\,{y_s}\ respectively. What force will arise in the plates if the temperature is increased by t0 c ? (Assume that the plates suffer the same net expansion) 

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a

\frac{{A{y_c}{y_s}\left( {{\alpha _c} - {\alpha _s}} \right)}}{{{y_s} + {y_c}}}\

b

\frac{{A{y_c}{y_s}\left( {{\alpha _c} - {\alpha _s}} \right)}}{{2{y_s} + {y_c}}}\

c

\frac{{2A{y_c}{y_s}\left( {{\alpha _c} - {\alpha _s}} \right)}}{{2{y_s} + {y_c}}}\

d

\frac{{2A{y_c}{y_s}\left( {{\alpha _c} - {\alpha _s}} \right)}}{{{y_s} + {y_c}}}\

answer is A.

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Detailed Solution

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Thermal expansion of cu = \ell {\alpha _c}t\ . Elastic contraction of cu = \frac{F}{A} \times \frac{{\ell _{}^{}}}{{{y_c}}}\   Net expansion of  cu = \ell {\alpha _c}t - \frac{F}{A}\frac{\ell }{{{y_c}}}\. Either steel plate is subjected to the tensile force \frac{F}{2}\  from the sides of the cu plate .Net expansion of steel =\ell {\alpha _s}t + \frac{F}{{2A}} \times \frac{l}{{{y_s}}}\  The plus sign is on account of the fact that there is elastic expansion, of steel plates. Since the plates suffer same net expansion 

\therefore \ell {\alpha _c}t - \frac{F}{A}.\frac{{\ell _{}^{}}}{{{y_c}}} = \ell {\alpha _s}t + \frac{F}{{2A}}.\frac{\ell }{{{y_s}}}\,\,solving\,\,we\,\,get\,\,F = \frac{{2A{y_c}{y_s}\left( {{\alpha _c} - {\alpha _s}} \right)}}{{2{y_s} + {y_c}}}

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