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The lattice energies of the carbonates of $Mg, Ca, Sr$ and $Ba$ follow the order

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${MgCO}_{3} > {CaCO}_{3} > {SrCO}_{3} > {BaCO}_{3}$

${CaCO}_{3} > {SrCO}_{3} > {BaCO}_{3} > {MgCO}_{3}$

${BaCO}_{3} > {SrCO}_{3} > {CaCO}_{3} > {MgCO}_{3}$

latex>\mathrm{SrCO}_{3}>\mathrm{MgCO}_{3}>\mathrm{CaCO}_{3}>\mathrm{BaCO}_{3}

answer is A.

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Detailed Solution

The smaller the size of the cation, the grater is the lattice energy.

correct answer:

option(a)

${MgCO}_{3} > C a C O_{3} > S r C O_{3} > B a C O_{3}$

,This is because with the increase ionic radius, the lattice energy decreases.

option(b),(c),(d): All the carbonates are of group 2 elements so lattice energy decreases going down the group.

The correct answer is option(a)

The lattice energies of the carbonates of Mg,Cr,Sr and Ba is

${MgCO}_{3} > C a C O_{3} > S r C O_{3} > B a C O_{3}$

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