No. of molecules present in 18 grams of $H_{2} O$

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$6.02 \times 10^{22}$

$6.02 \times 10^{23}$

$6.02 \times 10^{32}$

$6.02 \times 10^{35}$

answer is B.

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Detailed Solution

According to Rules in mole concept “The formula weight in grams represents the mass of one mole of that substance so, in the given question 18 grams of $H_{2} O$ , and we know one mole of any substance contains $6.02 \times 10^{23}$ particles.

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