No of moles of valence electrons present in 6.022×1023 of NH4+ ions is----

In one NH4+ ion 8 valence electronsIn 1 mole of NH4+ ions 8 mole of valence electrons

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No of moles of valence electrons present in $6.022 \times 10^{23} o f N H_{4}^{+}$ ions is----

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answer is 8.

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In one $\overset{+}{N H_{4}}$ ion 8 valence electrons

In 1 mole of $\overset{+}{N H_{4}}$ ions 8 mole of valence electrons

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