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Q.

No of selections of 6 different letters can be made from the words NISHIT and RAHUL so that each selection consists of 3 letters from each word is

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answer is 64.

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Detailed Solution

Case-1: H included in RAHUL $\Rightarrow$ excluded in NISHIT
$4_{C_{2}} \cdot 4_{C_{3}} = 6 \times 4 = 24$
Case:2: H excluded in RAHUL $\Rightarrow$ no constrain in NISHIT
$4_{C_{3}} \cdot 5_{C_{3}} = 40 w a y s$
Total 64 ways.

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