No. of unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1g is A.BC × 1021 then A.BC is ___ (atomic masses : Na = 23, Cl = 35.5)

One unit cell contains 4 molecules of NaCl. one mole of NaCl (58.5 g) contains 6.023×10234 unit cells then 1g of NaCl contains 6.023×10234×58.5 unit cells.

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No. of unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1g is A.BC × 10²¹ then A.BC is ___ (atomic masses : Na = 23, Cl = 35.5)

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answer is 2.57.

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Detailed Solution

One unit cell contains 4 molecules of NaCl. one mole of NaCl (58.5 g) contains $\frac{6 .023 \times 10^{23}}{4}$ unit cells then 1g of NaCl
$contains \frac{6 .023 \times 10^{23}}{4 \times 58 .5} unit cells.$