NO2 and N2O4 are two forms of nitrogen dioxide. One exists in gaseous state while other in liquid state. The nature of NO2 and N2O4 forms are

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${NO}_{2} and N_{2} O_{4}$ are two forms of nitrogen dioxide. One exists in gaseous state while other in liquid state. The nature of ${NO}_{2} and N_{2} O_{4}$ forms are

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both are paramagnetic

both are diamagnetic

${NO}_{2}$ is paramagnetic while $N_{2} O_{4}$ is diamagnetic

${NO}_{2}$ is diamagnetic while $N_{2} O_{4}$ is paramagnetic

answer is C.

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Detailed Solution

${NO}_{2}$ is an odd electron molecule (paramagnetic)

The dimer, $N_{2} O_{4}$ has no unpaired electron.(diamagnetic)

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