Nodal planes of $π$ bond(s) in ${CH}_{2} = C = C = {CH}_{2}$ are located in :

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one in molecular plane and two in plane perpendicular to molecular plane which contains $C - C$ $σ$ -bond

two in molecular plane and one in a plane perpendicular to molecular plane which bisects $C - C$ $σ$ -bond at right angle

two in molecular plane and one in a plane perpendicular to molecular plane which contains $C - C$ $σ$ -bond

all are in molecular plane

answer is B.

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Detailed Solution

In ${CH}_{2} = C = C = {CH}_{2}$ , there are three nodal planes for $π$ -bonds: two in the molecular plane and one in a plane that is perpendicular to the molecular plane and contains the $C — C$ $σ$ -bond.

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