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Normal molar mass and observed molar mass of a solute dissolved in a solvent are 60g and 80g respectively. True statement about degree of association of the solute in the solution is

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60% dimerized

75% dimerized

40% dimerized

50% dimerized

answer is A.

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Detailed Solution

$i = \frac{Normal molar mass}{Observed molar mass}; i = \frac{60}{80} = 0.75$

$i = 1 - α + \frac{α}{n} (n = 2 for dimerization)$
$i = 1 - \frac{α}{2}$
$\frac{α}{2} = (1 - 0 .75)$
$α = 0 .5$

Hint ; Since $M_{obs} > M_{Nor}$ , solute molecules get associated.

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