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Not considering the electronic spin the degeneracy or the second excited state $(n = 3)$ of $H -atom$ is 9, whereas the degeneracy of the second excited state of $H^{-}$ is :

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answer is 3.

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Detailed Solution

degeneracy = 9 for $H -atom$ because $3 s = 3 p = 3 d$

for $H^{-} 1 s < 2 s < 2 p < 3 s$

1st excited state 2s

2nd excited state 2p

Hence, degeneracy of 2nd excited state= 3

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