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Q.

Nucleus A having Z = 17 and equal number of protons and neutrons has 1.2 MeV binding energy per nucleon. Another nucleus B of Z=12 has total 26 nucleons and 1.8 MeV binding energy per nucleons. The difference of binding energy of B and A will be ___ MeV.

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a

$14 MeV$

b

$6 MeV$

c

$12 MeV$

d

$28 MeV$

answer is A.

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Detailed Solution

Binding energy of $A = 1.7 \times 2 \times 1.2$
$= 40.8 M e V$
Binding energy of $B = 26 \times 1.8$
$= 46.8 M e V$
Difference $= 46.8 - 40.8$ $\Rightarrow = 6 M e V$

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Nucleus A having Z = 17 and equal number of protons and neutrons has 1.2 MeV binding energy per nucleon. Another nucleus B of Z=12 has total 26 nucleons and 1.8 MeV binding energy per nucleons. The difference of binding energy of B and A will be ___ MeV.