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Q.

Nucleus  A is having mass number 220 and its binding energy per nucleon is 5.6 MeV . It splits in two fragments ' B  ' and '  C ' of mass numbers 105 and 115 respectively. The binding energies  of ' B  ' and ' C  ' are  6.4 MeV and 6.6 MeV per nucleon respectively. The energy (Q) released per fission will be 

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a

0.9 MeV 

b

220 MeV 

c

7.4 MeV 

d

199 MeV

answer is D.

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Detailed Solution

A220→ B105+C115
Q=6.4×105+6.6×115−5.6×220MeV=199MeV

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