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Number of ways in which 3 sovereings be given away to 4 applicants and any applicant may have either 0, 1, 2 and 3 sovereings is

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answer is D.

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Detailed Solution

_{$x_{1} + x_{2} + x_{3} + x_{4} = 3$}

_{$=^{3 + 4 - 1} c_{4 - 1} =^{6} c_{3} = 20$}

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