Q.

Number of π -bonding electrons in C22 is X
Number of π -bonding electrons in C2 is Y
Number of σ - bonding electrons in B2 is Z
Find the value of (X + Y – Z)
Consider all given species are in electronically ground energy state
 

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answer is 4.

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Detailed Solution

i) C22(14)σ1s2σ1s2*σ2s2 σ2s2*π2px2π2py2σ2pz2  
X = 4
ii) C2(12)σ1s2σ1s2*σ2s2 σ2s2*π2px2π2py2  
Y = 2
iii) B2(10)σ1s2σ1s2*σ2s2 σ2s2*π2px1π2py1 
Z = 4
X + Y + Z = 10 

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