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Q.

Number of antibonding electrons in N2 is :

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a

12

b

10

c

14

d

4

answer is A.

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Detailed Solution

N27(2)=14e-

N2(14):σ1s2σ*1s2σ2s2σ*2s2π2px2π2py2σ2pz2

e-(BMO)=10

e-(ABMO)=4

Number of antibonding electrons in N2 is 4.

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