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Q.

Number of atoms in 1 ml of ammonia gas at STP is

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a

$10.8 \times 10^{20}$

b

$5.4 \times 10^{19}$

c

$1.08 \times 10^{20}$

d

$2.7 \times 10^{19}$

answer is B.

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Detailed Solution

$At STP, 22400 mL o f {NH}_{3} \equiv 4 N_{A} atoms$

$1 mL o f {NH}_{3} \equiv \frac{4 \times 6 \times 10^{23}}{22400} atoms$

$= 1.08 \times 10^{20} atoms$

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