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Q.

Number of atoms in 558.5 gram Fe (At. Wt of Fe = 55.85g $m o l^{- 1}$ ) is

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a

Half that in 8g He

b

$6.023 \times 10^{22}$

c

Twice that in 60g carbon

d

$558.6 \times 6.023 \times 10^{23}$

answer is A.

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Detailed Solution

55.85 gm of Fe contain N atoms of Fe

558.5 gms of Fe contain 10N atom of Fe

12 gms of carbon contain N atoms.

60 gms of carbon contain 5N atoms

$∴$ Twice that in 60 gm carbon.

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