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Number of atoms in 558.5 gram Fe (at.wt of Fe=55.85 g mol^–1) is

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Twice that in 60 g carbon

6.023×10²²

Half that in 8g He

558.6×6.023×10²³

answer is A.

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Detailed Solution

GAW of Fe = 55.85g

55.85g of Fe contain N_A atoms

558.5g of Fe contain 'X' atoms

X = 10N_A

Option (1)

12g 'C' contain N_A atoms

60g 'C' contain 'X₁' atoms

X₁ = 5N_A atoms

Option (2)

6.023 x 10²²

Option (3)

4g of He contain N_A atoms

8g of He contain 'X₂' atoms

X₂ = 2N_A atoms

Option (4)

558.6 x 6.023 x 1022 atom

558.5g of Fe contain 10N_A atoms which are twice the atoms as present in 60g of 'C'(5N_A)

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