Number of atoms present in 64 grams of oxygen O 816 is

We know that 16 g of oxygen atom is equal to 1 mol of O . The weight of one mol of oxygen atom is equal to 6.023×1023 atoms. The number of moles present in 64g of oxygen is1 mol16 g of O×64 g of O = 4 molSo, there are 4×6.023×1023 oxygen atoms are present in 64 g of oxygen.

Number of atoms present in 64 grams of oxygen O 816 is

We know that 16 g of oxygen atom is equal to 1 mol of O . The weight of one mol of oxygen atom is equal to 6.023×1023 atoms. The number of moles present in 64g of oxygen is1 mol16 g of O×64 g of O = 4 molSo, there are 4×6.023×1023 oxygen atoms are present in 64 g of oxygen.

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Number of atoms present in 64 grams of oxygen ${}_{8}^{16}O$ is

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$4 \times 6.023 \times 10^{23}$

$2 \times 6.023 \times 10^{23}$

$6.023 \times 10^{23}$

answer is A.

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Detailed Solution

We know that 16 g of oxygen atom is equal to 1 mol of O . The weight of one mol of oxygen atom is equal to $6.023 \times 10^{23}$ atoms. The number of moles present in 64g of oxygen is

$\frac{1 mol}{16 g of O} \times 64 g of O = 4 mol$

So, there are $4 \times 6.023 \times 10^{23}$ oxygen atoms are present in 64 g of oxygen.

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