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Q.

Number of divisors of the form 4n+2  ,(n0) of the integer 240 is

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a

8

b

6

c

4

d

5

answer is A.

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Detailed Solution

240=243151

 Number of divisors of 240 are 

5 x 2 x 2 = 20 as listed below

1,2,4,8,16=202122232413,6,12,24,48=()35,10,20,40,80=0.515,30,60,120,240=()3×5

But only 2, 6, 10, 30 of column (2) correspond to the form

4n+2 for n=0,1,2,7

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