Number of electrons in 1.8 grams of ${\mathrm{H}}_2\mathrm{O}$ are

No. of electrons in ${\mathrm{H}}_2\mathrm{O} \mathrm{molecules} =10{\mathrm{e}}^{-}$

No. of electron in 1 mole (or) 18 gram ${\mathrm{H}}_2\mathrm{O}=10 \mathrm{mole} {\mathrm{e}}^{-}$

No. of electrons in 1.8 gram ${\mathrm{H}}_2\mathrm{O}=1 \mathrm{mole} {\mathrm{e}}^{-}$

$=6.023\times {10}^{23}$