Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

Number of electrons present in 4f orbital of Ho+3 ion is ______.

(given atomic number of Ho=67 )

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 10.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

  • The atomic number of Ho is known to be 67, so its electronic configuration will be written as Xe4f116s2.
  • The ion given in the question is Ho+3, so it is the ion of Ho with +3 electron charge, that is, its three outermost electrons are removed from their respective orbitals. So the electronic configuration of Ho+3 would be Xe4f10.

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon