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Number of electrons transferred in each case when ${KMnO}_{4}$ acts as an oxidising agent to
give ${MnO}_{2}, {Mn}^{2 +}, Mn (OH)_{3}, and {MnO}_{4}^{2 -},$ are respectively

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1,3,4 and 5

3,5,4 and 1

4,3,1 and 5

5,4,3 and 1

answer is A.

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Detailed Solution

$\begin{aligned} M^{7 +} + 3 e^{-} \to {Mn}^{4 +}; {Mn}^{7 +} + 5 e^{-} \to {Mn}^{2 +} \\ {Mn}^{7 +} + 4 e^{-} \to {Mn}^{3 +}; {Mn}^{7 +} + e^{-} \to {Mn}^{6 +} \end{aligned}$

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